The idea came from Orimdam here.
Mathematical background
The golden ratio means the following:
a:b=b:(a+b)
which is equal with this:
a*(a+b)=b^2
furthermore
a^2+ab=b^2
b^2-ab-a^2=0
which results as b=(a+-(a^2+4a^2)^0.5)/2=a*(1+5^0.5)/2
thus the golden ratio can be written in a more direct form:
a:b=1:((5^0.5+1)/2),
and 1:((5^0.5+1)/2)=((5^0.5-1)/2):(((5^0.5-1)/2)*(5^0.5+1)/2)=(5^0.5-1)/2:1
-which makes the connection to Fibonacci.
To construct the golden ratio, we will have to draw this (5^0.5-1)/2 ration.
We will use a right-angled triangle which has a leg double times longer than the other.
The ratio between the sides will be then 1:5^0.5:2 by Pytahgoras theorem, this is what the construction uses.
If the shorter leg's length is subtracted from the hypotenuse, it will make the golden ratio with the longer leg.
Here are the steps how it looks like all in inkscape:
It might not be simpe or fast if you doing it for the first time -or if you making a tutorial of it...-, but
it doesn't take much more time than opening the calculator from the accessories, typing in ((5^0.5)+1)/2 and multiply it with the smaller size of a rectangle, to get the longer size's correct width, that you type in to have the same result as with the construction method.
construction of a golden-proportion-rectangle
Re: construction of a golden-proportion-rectangle
It seems like a lot more work than necessary! ... In the thread you referred to, I had a much simpler method, did you see it? In the interests of anyone who might actually be looking at this thread for instructions on how to construct a rectangle of these proportions, I am posting the method again here, with annotations in case my other diagram was too difficult to follow. I. Draw a square.
2. Duplicate it.
4. Resize the duplicate from one side until the edge snaps to any midpoint of the original square.
5. Rotate this rectangle until the diagonal is horizontal (use a grid or guide).
6. Resize the original square to snap the corner to the farthest corner of the rotated rectangle.
Not even sure how that happens when it takes me so long to write the post!
BTW Ragnar, have I made any errors?
Off topic:
Incidentally, this can be done with nothing but a straightedge and compass, the way geometry was done originally.2. Duplicate it.
4. Resize the duplicate from one side until the edge snaps to any midpoint of the original square.
5. Rotate this rectangle until the diagonal is horizontal (use a grid or guide).
6. Resize the original square to snap the corner to the farthest corner of the rotated rectangle.
Off topic:
brynn wrote:WOW!!
Looking forwards to druban's comments.
And look, he managed to post them before I could even post!
Not even sure how that happens when it takes me so long to write the post!
BTW Ragnar, have I made any errors?
Last edited by druban on Tue Feb 12, 2013 9:46 pm, edited 2 times in total.
Your mind is what you think it is.
Re: construction of a golden-proportion-rectangle
WOW!!
Looking forwards to druban's comments.
And look, he managed to post them before I could even post!
Looking forwards to druban's comments.
And look, he managed to post them before I could even post!
Basics - Help menu > Tutorials
Manual - Inkscape: Guide to a Vector Drawing Program
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Inkscape for Cutting Design
Manual - Inkscape: Guide to a Vector Drawing Program
Inkscape Community - Inkscape FAQ - Gallery
Inkscape for Cutting Design
Re: construction of a golden-proportion-rectangle
Hi druban
I managed to draw a golden ratio box using your method - I could not find any error's!!
It would be nice to have a extension in Inkscape to make a golden ratio gauge or ruler - an electronic version of what draftsmen use;
http://familywoodworking.org/forums/showthread.php?14892-Fibonacci-Gauge-project
http://www.scrollsaws.com/WoodLathe/woodlathefibonacc.htm
http://www.scrollsaws.com/images/Lathe/RicksGuage.pdf
RGDS
Ragnar
RGDS
Ragnar
Off topic:
brynn wrote:WOW!!
Looking forwards to druban's comments.
Image And look, he managed to post them before I could even post!
Not even sure how that happens when it takes me so long to write the post!
BTW Ragnar, have I made any errors?
I managed to draw a golden ratio box using your method - I could not find any error's!!
It would be nice to have a extension in Inkscape to make a golden ratio gauge or ruler - an electronic version of what draftsmen use;
http://familywoodworking.org/forums/showthread.php?14892-Fibonacci-Gauge-project
http://www.scrollsaws.com/WoodLathe/woodlathefibonacc.htm
http://www.scrollsaws.com/images/Lathe/RicksGuage.pdf
RGDS
Ragnar
RGDS
Ragnar
Good Luck!
( ͡° ͜ʖ ͡°)
RGDS
Ragnar
( ͡° ͜ʖ ͡°)
RGDS
Ragnar
Re: construction of a golden-proportion-rectangle
druban wrote:It seems like a lot more work than necessary! ... In the thread you referred to, I had a much simpler method, did you see it? In the interests of anyone who might actually be looking at this thread for instructions on how to construct a rectangle of these proportions, I am posting the method again here, with annotations in case my other diagram was too difficult to follow.
I. Draw a square.
2. Duplicate it.
4. Resize the duplicate from one side until the edge snaps to any midpoint of the original square.
5. Rotate this rectangle until the diagonal is horizontal (use a grid or guide).
6. Resize the original square to snap the corner to the farthest corner of the rotated rectangle.
It was a basic construction for those who don't use the snap tool -like me.
I should have searched for other methods then just applying a basic golden ratio constructioning to inkscape.
Now browsing some things that I never used in inkscape before, the problem looks even easier to solve than your method:
1. set guidelines around the background
2. set guidelines in golden ratio in extensions/guideline maker
3. draw a rectangle-square from the edge guideline of the document (holding down Ctrl) until you snap the other corner on the next guideline paralell to the edge guideline
4. scale the square by holding the same corner horizontally (by holding down Ctrl again) until it snaps to the next guideline.