Is my logo to complicated to be converted to svg?

[OneTwentyFour]

When I trace my logo as a bitmap, it comes out looking like this, I also included a picture of my settings, I need to convert this to an svg somehow. Can somebody help?

[brynn]

Welcome to the forum!

That's happening because the logo is filled with a gradient.  And Trace Bitmap can only trace individual, or flat colors.

By any chance do you have a version of the logo without any color, or with a solid color?  If so, you could trace that, and then apply a gradient to it, in a 2nd step.

If not, you could use the Pen tool, and trace it "manually".  And then apply the gradient.  I'd be happy to help you learn how to use the Pen tool, and Gradient tool.  You might even have the gradient saved separately, somewhere, if you have had any plans to trademark the logo??  Or actually, I think there are 2 gradients (one for the logo and one for the drop shadow).

[Lazur]

By any chance do you have a version of the logo without any color, or with a solid color? 

It has a distinct alpha channel so theoretically it "should be" easy to handle such a task all within inkscape.

Select the raster image, duplicate it (Ctrl+D), and run the extension/raster/channel with opacity channel set from the dopdown list.
Then you'd have a "perfect" input for the trace bitmap.

However only the "top layer" of that image is filled with a gradient so it'd take a bit of manual working after.

Also, *most importantly*, the basic image is way too small for getting out decent details of it.
It's not that inkscape can't handle your image but there is nothing to handle.
Could use a raster editor for blowing it up yet it could make previously sharp corners rounded.

[Moini]

The trace bitmap dialog already has a threshold setting.

Use that until it vectorizes the whole drawing in a single color.

Later, apply the gradient and the other colors to the separate objects (do Path > Break apart, and combine all the objects that share a gradient into one for each gradient with Path > Combine, then apply the gradient).